## Chemistry: The Molecular Science (5th Edition)

$1 BaCrO_4(s) \lt -- \gt 1Ba^{2+}(aq) + 1Cr{O_4}^{2-}(aq)$ $K_{sp} (BaCrO_4) = [Ba^{2+}][Cr{O_4}^{2-}]$
1. Write the dissociation equation for this salt: - Identify the ions of the salt: $(Ba^{2+})$ and $(Cr{O_4}^{2-})$, these are the products, and the reactant is the solid salt. $BaCrO_4(s) \lt -- \gt Ba^{2+}(aq) + Cr{O_4}^{2-}(aq)$ - Balance the equation: $1 BaCrO_4(s) \lt -- \gt 1Ba^{2+}(aq) + 1Cr{O_4}^{2-}(aq)$ 2. Now, write the $K_{sp}$ expression. - Multiply the concentrations of the ions; - The equilibrium coefficients represent the exponent of these concentrations: $K_{sp} (BaCrO_4) = [Ba^{2+}]^1 \times [Cr{O_4}^{2-}]^1$