Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 51c


$1PbCO_3(s) \lt -- \gt 1Pb^{2+}(aq) + 1C{O_3}^{2-}(aq)$ $K_{sp} (PbCO_3) = [Pb^{2+}][C{O_3}^{2-}]$

Work Step by Step

- Lead (II) $(Pb^{2+})$ carbonate $(C{O_3}^{2-})$: $PbCO_3$ 1. Write the dissociation equation for this salt: - Identify the ions of the salt: $(Pb^{2+})$ and $(C{O_3}^{2-})$, these are the products, and the reactant is the solid salt. $PbCO_3(s) \lt -- \gt Pb^{2+}(aq) + C{O_3}^{2-}(aq)$ - Balance the equation: $1PbCO_3(s) \lt -- \gt 1Pb^{2+}(aq) + 1C{O_3}^{2-}(aq)$ 2. Now, write the $K_{sp}$ expression. - Multiply the concentrations of the ions; - The equilibrium coefficients represent the exponent of these concentrations: $K_{sp} (PbCO_3) = [Pb^{2+}]^1 \times [C{O_3}^{2-}]^1$
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