# Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 41d

The necessary volume for this titration is $2.7ml$ of $HCl$

#### Work Step by Step

- Notice: $Ba(OH)_2$ has 2 $OH^-$ that can be donated; therefore, if its concentration is $0.005M$, the hydroxide molarity is doubled: $0.010M$ 1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = C_2 * V_2$ $0.010* 40= 0.15 * V_2$ $0.4 = 0.15 * V_2$ $V_2 = 2.7 ml$

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