Answer
The necessary volume for this titration is $2.7ml$ of $HCl$
Work Step by Step
- Notice: $Ba(OH)_2$ has 2 $OH^-$ that can be donated; therefore, if its concentration is $0.005M$, the hydroxide molarity is doubled: $0.010M$
1. Find the volume necessary for an equal number of moles:
$C_1 * V_1 = C_2 * V_2$
$ 0.010* 40= 0.15 * V_2$
$ 0.4 = 0.15 * V_2$
$V_2 = 2.7 ml$
