Answer
$1FeCO_3(s) \lt -- \gt 1Fe^{2+}(aq) + 1C{O_3}^{2-}(aq)$
$K_{sp} (FeCO_3) = [Fe^{2+}] [C{O_3}^{2-}]$
Work Step by Step
- Iron (II) $(Fe^{2+})$ carbonate $(C{O_3}^{2-})$: $FeCO_3$
1. Write the dissociation equation for this salt:
- Identify the ions of the salt: $(Fe^{2+})$ and $(C{O_3}^{2-})$, these are the products, and the reactant is the solid salt.
$FeCO_3(s) \lt -- \gt Fe^{2+}(aq) + C{O_3}^{2-}(aq)$
- Balance the equation:
$1FeCO_3(s) \lt -- \gt 1Fe^{2+}(aq) + 1C{O_3}^{2-}(aq)$
2. Now, write the $K_{sp}$ expression.
- Multiply the concentrations of the ions;
- The equilibrium coefficients represent the exponent of these concentrations:
$K_{sp} (FeCO_3) = [Fe^{2+}]^1 \times [C{O_3}^{2-}]^1$
