The necessary volume for this tritation is $29.2$ ml of $HCl$
Work Step by Step
1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = C_2 * V_2$ $ 0.175* 25= 0.15 * V_2$ $ 4.375 = 0.15 * V_2$ $V_2 = 29.2$ ml.
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