Answer
The necessary volume for this tritation is $29.2$ ml of $HCl$
Work Step by Step
1. Find the volume necessary for an equal number of moles:
$C_1 * V_1 = C_2 * V_2$
$ 0.175* 25= 0.15 * V_2$
$ 4.375 = 0.15 * V_2$
$V_2 = 29.2$ ml.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 41a
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