Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 51b


$1Mn(OH)_2(s) \lt -- \gt 1Mn^{2+}(aq) + 2OH^-(aq)$ $K_{sp} (Mn(OH)_2) = [Mn^{2+}][OH^-]^2$

Work Step by Step

1. Write the dissociation equation for this salt: - Identify the ions of the salt: $(Mn^{2+})$ and $(OH^-)$, these are the products, and the reactant is the solid salt. $Mn(OH)_2(s) \lt -- \gt Mn^{2+}(aq) + OH^-(aq)$ - Balance the equation: $1Mn(OH)_2(s) \lt -- \gt 1Mn^{2+}(aq) + 2OH^-(aq)$ 2. Now, write the $K_{sp}$ expression. - Multiply the concentrations of the ions; - The equilibrium coefficients represent the exponent of these concentrations: $K_{sp} (Mn(OH)_2) = [Mn^{2+}]^1 \times [OH^-]^2$
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