## Chemistry: The Molecular Science (5th Edition)

Bromthymol blue is the most suitable, because it changes its color in neutral solutions, and the equivalence point of the titration between $KOH$ and $HNO_3$ is in neutral solution.
$HNO_3$ is a strong acid and $KOH$ is a strong base; therefore, the pH at the equivalence point of their titration will be neutral $(pH = 7)$. Analyzing the 3 given indicators on page 667, the one where the color changes in neutral solution is the most appropriate, so Bromthymol blue is the correct answer.