# Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 41b

The necessary volume for this titration is $600ml$ of $HCl$.

#### Work Step by Step

1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = C_2 * V_2$ $6.0* 15= 0.15 * V_2$ $90 = 0.15 * V_2$ $V_2 = 600 ml$

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