The necessary volume for this titration is $600ml$ of $HCl$.
Work Step by Step
1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = C_2 * V_2$ $ 6.0* 15= 0.15 * V_2$ $ 90 = 0.15 * V_2$ $V_2 = 600 ml$
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