#### Answer

131 mL

#### Work Step by Step

$V_{conc}=100.\,mL$
$ c_{conc}=1.44\,M$ (obtained in part (a))
$c_{dil}=1.10\,M$
$c_{conc}\times V_{conc}= c_{dil}\times V_{dil}$
$\implies V_{dil}=\frac{c_{conc}\times V_{conc}}{c_{dil}}=\frac{1.44\,M\times100\,mL}{1.10\,M}$
$=131\,mL$