Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 44c


7.46 g $Na_{2}SO_{4}$

Work Step by Step

Molarity M= 0.350 M Volume of solution in litre V= 0.150 L Number of moles of solute n=MV=$0.350M\times.150L= 0.0525 mol$ Mass in grams= n$\times$ Molar mass of $Na_{2}SO_{4}$ $= 0.0525 mol\times142.04 g/mol=7.46 g$
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