Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 46d


0.167 M

Work Step by Step

Molarity=$ \frac{Number\,of\,moles\,of\,C_{6}H_{12}O_{6}}{Volume\, of\, solution\,in\,L}=\frac{\frac{Mass\,of\,C_{6}H_{12}O_{6}}{Molar\,mass}}{Volume\,of\, solution\,in\,L}$ $=\frac{\frac{15.0\,g}{180.g/mol}}{500.\times10^{-3}L}=0.167\,M$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.