Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 54


0.764 M

Work Step by Step

Mass fraction of sucrose$=\frac{23.2}{100}=0.232$ Let the volume of the solution be 1 L=1000 mL. Then, mass of the solution=$density\times volume$ $= 1.127\,g/mL \times1000\,mL=1127\,g$ Mass of sucrose= mass fraction$\times$ mass of the solution $=0.232\times1127\,g=261.464\,g$ Molar mass of sucrose ($C_{12}H_{22}O_{11}$) =342.3 g/mol Moles of sucrose= $\frac{mass\,of\, sucrose}{molar\,mass}=\frac{261.464\,g}{342.3\,g/mol}$ $=0.764\,mol$ Molarity of sucrose= $\frac{moles\,of\, sucrose}{volume\, of\, solution\,in\,L}=\frac{0.764\,mol}{1\,L}=0.764\,M$
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