Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 48



Work Step by Step

Molarity = 18 M=$ \frac{18\,mol}{1\,L}$ We can find the mass of sulphuric acid from the number of moles. 18 mol sulphuric acid= $18 \,mol\times\frac{98.079\,g}{1\,mol}$ $= 1765.422 g$ $1\,L \, solution= 1000 cm^{3}\, solution$ Mass of solution = Density$\times$Volume= $1.84\,g/cm^{3}\times 1000\,cm^{3}=1840\,g $ Mass fraction of $H_{2}SO_{4}=\frac{mass\,of\,H_{2}SO_{4}}{mass\, of\, solution}$ $=\frac{1765.422\,g}{1840\,g}=0.96$ Weight percent= mass fraction$\times100\%$ $=0.96\times100\%=96\%\,H_{2}SO_{4}$
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