Answer
96%
Work Step by Step
Molarity = 18 M=$ \frac{18\,mol}{1\,L}$
We can find the mass of sulphuric acid from the number of moles.
18 mol sulphuric acid= $18 \,mol\times\frac{98.079\,g}{1\,mol}$
$= 1765.422 g$
$1\,L \, solution= 1000 cm^{3}\, solution$
Mass of solution = Density$\times$Volume=
$1.84\,g/cm^{3}\times 1000\,cm^{3}=1840\,g $
Mass fraction of $H_{2}SO_{4}=\frac{mass\,of\,H_{2}SO_{4}}{mass\, of\, solution}$
$=\frac{1765.422\,g}{1840\,g}=0.96$
Weight percent= mass fraction$\times100\%$
$=0.96\times100\%=96\%\,H_{2}SO_{4}$
