Answer
1.44 M
Work Step by Step
Weight percent= 13.0%
Mass fraction= 13.0/100= 0.130
Let the volume of the solution be 1 L= 1000 mL. Then,
Mass of the solution= Density$\times$Volume= $1.090\,g/mL \times 1000\,mL= 1090\,g $
Mass of $H_{2}SO_{4}$= mass fraction of $H_{2}SO_{4}\times$ mass of the solution
$=0.130\times1090\,g=141.7\,g$
Moles of $H_{2}SO_{4}=\frac{mass\,of\,H_{2}SO_{4}}{molar\,mass}$
$=\frac{141.7\,g}{98.079\,g/mol}=1.44\,mol$
Molarity=$ \frac{mass\,of\,H_{2}SO_{4}}{Volume\, of\, solution\,in\,L}=\frac{1.44\,mol}{1\,L}$
$=1.44\,M$
