Answer
0.0126 M
Work Step by Step
Molarity=$ \frac{Number\,of\,moles\,of\,KMnO_{4}}{Volume\, of\, solution\,in\,L}=\frac{\frac{Mass\,of\,KMnO_{4}}{Molar\,mass}}{Volume\,of\, solution\,in\,L}$
$=\frac{\frac{0.799g}{158g/mol}}{0.400L}=0.0126\,M$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 46c
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