Work Step by Step
Molarity M= 0.50 M Volume of solution in litre V= 0.250 L Number of moles of solute n=MV=$0.50M\times.250L= 0.125\, mol$ Mass in grams= n$\times$ Molar mass of $NaCl$ $= 0.125 mol\times58.44 g/mol=7.3\, g$
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