Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 46a


0.762 M

Work Step by Step

Molarity=$ \frac{Number\,of\,moles\,of\,KCl}{Volume\, of\, solution\,in\,L}=\frac{\frac{Mass\,of\,KCl}{Molar\,mass}}{Volume\,of\, solution\,in\,L}$ $=\frac{\frac{14.2g}{74.55g/mol}}{0.250L}=0.762\,M$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.