Answer
See explanation
Work Step by Step
To find the noble gas with the same electron configuration as each ion, we look at how many electrons each atom gains or loses when forming the compound. Then we match the resulting ion to the nearest noble gas.
a. Cesium sulfide (Cs2S):
Cs+: Cesium loses 1 electron $\rightarrow$ electron configuration matches xenon (Xe)
S2-: Sulfur gains 2 electrons $\rightarrow$ electron configuration matches argon (Ar)
b. Strontium fluoride (SrF2):
Sr2+: Strontium loses 2 electrons $\rightarrow$ electron configuration matches kripton (Kr)
F-: Flurine gains 1 electron $\rightarrow$ electron configuration matches neon (Ne)
c. Calcium nitride (Ca3N2):
Ca2+: Calcium loses 2 electrons $\rightarrow$ electron configuration matches argon (Ar)
N3-: Nitrogen gains 3 electrons $\rightarrow$ electron configuration matches neon (Ne)
d. Aluminum bromide (AlBr3):
Al3+: Aluminum loses 3 electrons $\rightarrow$ electron configuration matches neon (Ne)
Br-: Bromine gains 1 electron $\rightarrow$ electron configuration matches kripton (Kr)
