## Chemistry: Atoms First (2nd Edition)

a. This element with an atomic number of 13 is aluminum (Al). It would most likely lose electrons because it has three valence electrons it would readily give up to form Al$^{3+}$. b. This element with an atomic number of 34 is selenium (Se). It would most likely gain electrons because it has six valence electrons and would readily accept two more electrons to form Se$^{2-}$. c. This element with an atomic number of 56 is barium (Ba). It would most likely lose electrons because it has two valence electrons it would readily give up to form Ba$^{2+}$. d. This element with an atomic number of 7 is nitrogen (N). It would most likely gain electrons because it has five valence electrons and would readily accept three more electrons to form N$^{3-}$. e. This element with an atomic number of 87 is francium (Fr). It would most likely lose an electron because it has one valence electron and would readily lose this one electron to form Fr$^{+}$. f. This element with an atomic number of 35 is bromine (Br). It would most likely gain electrons because it has seven valence electrons and would readily accept one more electron to form Br$^{-}$.
a. This element with an atomic number of 13 is aluminum (Al). It would most likely lose electrons because it has three valence electrons it would readily give up to form Al$^{3+}$. b. This element with an atomic number of 34 is selenium (Se). It would most likely gain electrons because it has six valence electrons and would readily accept two more electrons to form Se$^{2-}$. c. This element with an atomic number of 56 is barium (Ba). It would most likely lose electrons because it has two valence electrons it would readily give up to form Ba$^{2+}$. d. This element with an atomic number of 7 is nitrogen (N). It would most likely gain electrons because it has five valence electrons and would readily accept three more electrons to form N$^{3-}$. e. This element with an atomic number of 87 is francium (Fr). It would most likely lose an electron because it has one valence electron and would readily lose this one electron to form Fr$^{+}$. f. This element with an atomic number of 35 is bromine (Br). It would most likely gain electrons because it has seven valence electrons and would readily accept one more electron to form Br$^{-}$.