Answer
a. This atom of radium would most likely lose electrons because it is an alkaline earth metal with two valence electrons it would readily give up to form Ra$^{2+}$.
b. This atom of indium would most likely lose electrons because it has three electrons in its outermost shell that it would most likely give up to form In$^{3+}$.
c. This atom of phosphorus would most likely gain electrons because it has five valence electrons and would readily accept three more electrons to form P$^{3-}$.
d. This atom of tellurium would most likely gain electrons because it has six valence electrons and would readily accept two more electrons to form Te$^{2-}$.
e. This atom of bromine would most likely gain one electron because it is a halogen and has seven valence electrons and would readily accept one more electron to form Br$^{-}$.
f. This atom of rubidium would most likely lose an electron because it is in the alkali metal group and has one valence electron and would readily lose one electron to form Rb$^{+}$.
Work Step by Step
a. This atom of radium would most likely lose electrons because it is an alkaline earth metal with two valence electrons it would readily give up to form Ra$^{2+}$.
b. This atom of indium would most likely lose electrons because it has three electrons in its outermost shell that it would most likely give up to form In$^{3+}$.
c. This atom of phosphorus would most likely gain electrons because it has five valence electrons and would readily accept three more electrons to form P$^{3-}$.
d. This atom of tellurium would most likely gain electrons because it has six valence electrons and would readily accept two more electrons to form Te$^{2-}$.
e. This atom of bromine would most likely gain one electron because it is a halogen and has seven valence electrons and would readily accept one more electron to form Br$^{-}$.
f. This atom of rubidium would most likely lose an electron because it is in the alkali metal group and has one valence electron and would readily lose one electron to form Rb$^{+}$.
