Answer
The order of the bonds from most polar to least polar is:
F-H > O-H > N-H > C-H > P-H
Work Step by Step
To rank the given bonds in order of decreasing polarity, we need to consider the electronegativity difference between the atoms involved in the bonds.
The electronegativity values of the elements are:
- Hydrogen (H): 2.20
- Carbon (C): 2.55
- Nitrogen (N): 3.04
- Oxygen (O): 3.44
- Fluorine (F): 3.98
- Phosphorus (P): 2.19
Based on the given information, the electronegativity of hydrogen is between boron (2.04) and carbon (2.55), and is identical to phosphorus (2.19).
Now, let's rank the bonds in order of decreasing polarity:
1. F-H: The electronegativity difference between fluorine (3.98) and hydrogen (2.20) is the largest, making the F-H bond the most polar.
2. O-H: The electronegativity difference between oxygen (3.44) and hydrogen (2.20) is the second-largest, making the O-H bond the second-most polar.
3. N-H: The electronegativity difference between nitrogen (3.04) and hydrogen (2.20) is the third-largest, making the N-H bond the third-most polar.
4. P-H: The electronegativity difference between phosphorus (2.19) and hydrogen (2.20) is the smallest, making the P-H bond the least polar.
5. C-H: The electronegativity difference between carbon (2.55) and hydrogen (2.20) is also small, making the C-H bond less polar than the F-H, O-H, and N-H bonds.
Therefore, the order of the bonds from most polar to least polar is:
F-H > O-H > N-H > C-H > P-H
