Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 188: 62

Answer

The molarity of the diluted solution is equal to $0.37 \space M \space SrCl_2$.

Work Step by Step

1. Write the dilution expression, and solve for $C_2$, since we want to know the final concentration (molarity). $C_1 \times V_1 = C_2 \times V_2$ $\frac{C_1 \times V_1}{V_2} = C_2$ 2. Substitute the given values into the expression: $\frac{(4.8 \space M ) \times (3.5 \space L)}{45 \space L} = C_2$ $0.37 \space M = C_2$ Thus, the final molarity of the solution is equal to $0.37 \space M \space SrCl_2$.
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