Answer
$0.645M$
Work Step by Step
To find the molarity we divide the number of moles of solute by the liters of solution.
$M= \frac{Moles\ solute}{Liters\ solution}$
So for this problem we get:
$72.8g\ C_{2}H_{6}O\times\frac{1mol\ C_{2}H_{6}O}{48.08g\ C_{2}H_{6}O}=1.51mol\\
\frac{1.51mol\ C_{2}H_{6}O}{2.34L}= 0.645M$
