Chemistry: A Molecular Approach (3rd Edition)

$1.8\times10^{-2}$ $g$ $CaCl_{2}$
Use molarity as a conversion factor in order to convert liters into moles. The use molar mass to convert from moles into grams. $5.5 L$ $CaCl_{2}$ $\times\frac{0.300 mol CaCl_{2}}{1 L CaCl_{2}}$$\times\frac{110.984 g CaCl_{2}}{1 mol CaCl_{2}}$$=1.8\times10^{-2}$ $g$ $CaCl_{2}$