Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 188: 60


$1.8\times10^{-2}$ $g$ $CaCl_{2}$

Work Step by Step

Use molarity as a conversion factor in order to convert liters into moles. The use molar mass to convert from moles into grams. $5.5 L$ $CaCl_{2}$ $\times\frac{0.300 mol CaCl_{2}}{1 L CaCl_{2}}$$\times\frac{110.984 g CaCl_{2}}{1 mol CaCl_{2}}$$=1.8\times10^{-2}$ $g$ $CaCl_{2}$
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