Answer
The molarity of the diluted glucose solution is equal to $0.27 \space M$
Work Step by Step
1. Write the dilution expression, and solve for $C_2$, since we want to know the final concentration (molarity).
$C_1 \times V_1 = C_2 \times V_2$
$\frac{C_1 \times V_1}{V_2} = C_2$
2. Substitute the given values into the expression:
$\frac{(1.1 \space M ) \times (123 \space mL)}{500.0 \space mL} = C_2$
$0.27 \space M = C_2$
Thus, the final molarity of the solution is equal to $0.27 \space M \space glucose$.
