Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 188: 54c



Work Step by Step

To find the molarity we divide the number of moles of solute by the liters of solution. $M= \frac{Moles\ solute}{Liters\ solution}$ So for this problem we get: $12.87mg\ KI\times\frac{1g}{1000mg}\times\frac{1mol\ KI}{166.0g\ KI}=7.753\times10^{-5}mol\\ 112.4mL\frac{1L}{1000mL}\\ \frac{7.753\times10^{-5}mol\ KI}{0.1124L}= 6.898\times10^{-4}M$
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