Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 188: 53a



Work Step by Step

To find the molarity we divide the number of moles of solute by the liters of solution. $M= \frac{Moles\ solute}{Liters\ solution}$ So for this problem we get: $\frac{3.25mol\ LiCl}{2.78L}= 1.17M$
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