Answer
$37$ $g$ $NaNO_{3}$
Work Step by Step
Use molarity as a conversion factor in order to convert liters into moles. The use molar mass to convert from moles into grams.
$400.0\times10^{-3}L$ $NaNO_{3}$ $\times\frac{1.1 mol NaNO_{3}}{1 L NaNO_{3}}$ $\times\frac{84.9947 g NaNO_{3}}{1 mol NaNO_{3}}$ $=37$ $g$ $NaNO_{3}$
