Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 188: 53c

Answer

4.53 x $10^{-3} M NaCl $

Work Step by Step

$ \frac{32.4 \times 10^{-3} g NaCl }{122.4 \times 10^{-3} L NaCl} \times \frac{1 mol NaCl}{58.44 g NaCl}=4.53 \times 10^{-3} M NaCl $
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