Answer
4.53 x $10^{-3} M NaCl $
Work Step by Step
$ \frac{32.4 \times 10^{-3} g NaCl }{122.4 \times 10^{-3} L NaCl} \times \frac{1 mol NaCl}{58.44 g NaCl}=4.53 \times 10^{-3} M NaCl $
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