Answer
$Fe_{3}O_{4}$ has the highest mass percentage composition of iron
Work Step by Step
1-Finding the percentage of iron in $Fe_{2}O_{3}$:
Molar mass of iron in $Fe_{2}O_{3}$=2×55.8=111.6
Total Molar mass of the compound=( 2×55.8 )+(3×16)=159.6
To calculate the mass percentage composition, divide molar mass of iron present in the compound by the total molar of compound:
111.6/159.6= 0.6992
Multiply the answer by 100 to find the percentage
0.6992×100= 69.92%
2-Finding the percentage of iron in $Fe_{3}O_{4}$:
Molar mass of iron in $Fe_{3}O_{4}$=3×55.8=167.4
Total molar mass of $Fe_{3}O_{4}$=( 3×55.8 )+(4×16)=231.4
To find the mass percentage composition of iron in the compound, divide molar mass of iron present in the compound by the total molar mass of the compound:
167.4/231.4 = 0.7234
Multiply by 100 to find the percentage.
0.7234x100= 72.34%
3- Finding the percentage of Iron in $FeCO_{3}:$
Molar mass of iron in $Fe_{3}O_{3}$=55.8
Total Molar mass of $Fe_{3}O_{3}$=55.8+12+(3×16)=115.8
To find the mass percentage composition of iron in the compound, divide molar mass of iron present in the compound by the total molar mass of the compound:
55.8 / 115.8= 0.481
Multiply by 100 to find the percentage.
0.481×100=48.1%
Therefore, it is seen that $Fe_{3}O_{4}$ has the highest mass percentage composition of iron.
