Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 63d

Answer

1093 mol $Na_{2}SO_{4}$

Work Step by Step

$\frac{155.2 kg Na_{2}SO_{4} }{1} \times \frac{1000 grams}{1 kg} \times\frac{1 mol Na_{2}SO_{4} }{142.042 grams Na_{2}SO_{4} }{} = 1093 mol Na_{2}SO_{4} $
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