Answer
1093 mol $Na_{2}SO_{4}$
Work Step by Step
$\frac{155.2 kg Na_{2}SO_{4} }{1} \times \frac{1000 grams}{1 kg} \times\frac{1 mol Na_{2}SO_{4} }{142.042 grams Na_{2}SO_{4} }{} = 1093 mol Na_{2}SO_{4} $
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