Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 64d


$3.48\times10^{3}$ $mols$ $CaO$

Work Step by Step

Convert kilograms into grams. Then use molar mass to convert grams into moles. $195 kg$ $CaO$$\times\frac{1000 g CaO}{1 kg CaO}$$\times\frac{1 mol CaO}{56.0774 g CaO} =$ $3.48\times10^{3}$ $mols$ $CaO$
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