Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 65d

Answer

$1.09\times10^{23}\ molecules$

Work Step by Step

Convert grams into moles using the molar mass then multiply by avagadro's number to get the number of molecules. $19.3g\ C_{8}H_{10}\times\frac{1mol\ C_{8}H_{10}}{106.17g\ C_{8}H_{10}}\times\frac{6.022\times10^{23}\ molecules}{1\ mol}= 1.09\times10^{23}\ molecules$
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