Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 61c


$$968 mols$$

Work Step by Step

Divide masses provided by the molecular mass of the molecule/element to find the mols. Molar mass of $C_2H_2 = 2\times(12.01, mass of carbon) + 2 \times (1, mass of hydrogen) = 26.02 g$ $\frac{25200g C_2H_2 in sample}{26.036gC_2H_2 per mole} \approx 968mol C_2H_2$
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