Answer
$$131molsFe(NO_{3})_{2}$$
Work Step by Step
Convert kilograms into grams, then use molar mass to convert from grams to moles.
$23.6$ $kg$ $Fe(NO_{3})_{2}\times\frac{1000 g Fe(NO_{3})_{2}}{1 kg Fe(NO_{3})_{2}}\times\frac{1 mol Fe(NO_{3})_{2}}{179.8548 g Fe(NO_{3})_{2}} =$ $131$ $mols$ $Fe(NO_{3})_{2}$