Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 63b


$$28.4 mols CO_{2}$$

Work Step by Step

Convert kilograms into grams. Then use molar mass to convert grams into moles. $1.25 g CO_{2}\times\frac{1000 g CO_2}{1 kg CO_2}\times\frac{1 mol CO_{2}}{44.0095 g CO_{2}}=28.4 mol CO_{2}.$
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