Answer
$$1.039\times10^{-3}molsC_{8}H_{18}$$
Work Step by Step
Use molar mass to convert from grams to moles.
$0.1187 g$ $C_{8}H_{18}$$\times\frac{1 mol C_{8}H_{18}}{114.2278 g C_{8}H_{18}} =$ $1.039\times10^{-3}$ $mols$ $C_{8}H_{18}$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 64c
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