Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 62b

Answer

$0.00354g\ H_{2}O_{2}$

Work Step by Step

$1.04\times10^{-4}mol\ H_{2}O_{2}\times\frac{34.015g\ H_{2}O_{2}}{1mol\ H_{2}O_{2}}= 0.00354g\ H_{2}O_{2}$
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