Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems: 3.29

Answer

Please see the work below.

Work Step by Step

As we know that $1.0\times 10^{-2}g\times \frac{1mol}{282.49g}\times \frac{6.022\times 10^{23}molecules}{1 mol}=2.1\times 10^9\space molecules$
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