Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.15

Answer

Please see the work below.

Work Step by Step

We know that $77.4g\space of \space Ca\times \frac{1mol\space Ca}{40.08g\space Ca}=1.93mol\space Ca$
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