Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems: 3.26

Answer

Please see the work below.

Work Step by Step

We know that $0.334g\space C_2H_5\times \frac{1mol\space C_2H_6}{30.068g\space C_2H_6}\times \frac{6.022\times 10^{23}C_2H_6molecules }{1mol\space C_2H_6}=6.69\times 10^{23}C_2H_6molecules$
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