Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.26

Answer

Please see the work below.

Work Step by Step

We know that $0.334g\space C_2H_5\times \frac{1mol\space C_2H_6}{30.068g\space C_2H_6}\times \frac{6.022\times 10^{23}C_2H_6molecules }{1mol\space C_2H_6}=6.69\times 10^{23}C_2H_6molecules$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.