Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.14

Answer

Please see the work below.

Work Step by Step

We know that $6.00\times 10^9 CO\space atoms\times \frac{1mol\space CO}{6.022\times 10^{23}CO\space atoms}=9.96\times 10^{-15}mol\space CO $
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