Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.16

Answer

Please see the work below.

Work Step by Step

We know that $15.3mol\space Au\times \frac{197.0g\space Au}{1mol\space Au}=3.01\times 10^3g\space Au$
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