Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems: 3.24

Answer

Please see the work below.

Work Step by Step

We can calculate the molar mass of the given substances as: a. $Li_2CO_3$ $2\times 6.941+12.011+3\times 15.9994=73.89$ b. $CS_2$ $12.011+2\times 32.06=76.13$ c. $CHCl_3$ $12.011+1+3\times 35.5=119.38$ d. $C_6H_8O_6$ $6\times 12.011+8\times 1+16\times 6=176.13$ e. $KNO_3$ $39+14+3\times 16=101.10$ f. $Mg_3N_2$ $3\times 24+2\times 14=100$
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