Answer
Please see the work below.
Work Step by Step
We know that
$1.00\times Pb\space atoms\times \frac{1mol\space Pb}{6.022\times 10^{23}Pb\space atoms}\times \frac{207.2g\space Pb}{1mol\space Pb}=3.44\times 10^{-10}g\space Pb$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.19
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