Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems: 3.17

Answer

Please see the work below.

Work Step by Step

We know that a.$ \frac{200.6g\space Hg}{1mol\space Hg}\times \frac{1mol\space Hg}{6.022\times 10^{23}Hg\space atoms}=3.331\times 10^{-21}\frac{g}{Hg\space Hg\space atom}$ b. $\frac{20.18g\space Ne}{1mol\space Ne}\times \frac{1mol\space Ne }{6.022\times 10^{23}Ne\space atoms}=3.351\times 10^{-23}\frac{g}{Ne}$
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