Answer
$1056$ ways.
Work Step by Step
- First, from the 12 remaining ranks, we must select two of them. They must be different.
It is a combination of 12 distinct ranks taken 2 at a time:
$_{12}C_2=\frac{12!}{2!(12-2)!}=\frac{12!}{2!\times10!}=\frac{12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1}{2\times1\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1}=66$
- Now, for each of the two ranks we have 4 choices:
First rank: 4 choices
Second rank: 4 choices
Using the Multiplication Rule of Counting (see page 298):
$66\times4\times4=1056$
