Answer
6
Work Step by Step
The modulus of this point on the complex plane so to speak is $\sqrt {a^2+b^2}$ where a+bi is the given number. So a is 6 and b is 0 and when we plug that into our modulus equation we get $\sqrt {(6)^2+0^2}$ or 6.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 8 - Section 8.3 - Polar Form of Complex Numbers; De Moivre's Theorem - 8.3 Exercises - Page 610: 8
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