Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.3 - Polar Form of Complex Numbers; De Moivre's Theorem - 8.3 Exercises - Page 610: 7

Answer

2
1501282849

Work Step by Step

The modulus of this point on the complex plane so to speak is $\sqrt {a^2+b^2}$ where a+bi is the given number. So a is -2 and b is 0 and when we plug that into our modulus equation we get $\sqrt {(-2)^2+0^2}$ or 2.
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