Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.3 - Polar Form of Complex Numbers; De Moivre's Theorem - 8.3 Exercises - Page 610: 12

Answer

$|z|=\displaystyle \frac{2\sqrt{3}}{3}$ see graph below .

Work Step by Step

See p. 602, Graphing Complex Numbers The complex plane is determined by the real axis and the imaginary axis. To graph the complex number a + bi, we plot the ordered pair of numbers (a,b) in this plane See p. 603, The modulus (or absolute value) of the complex number $z=a+bi$ is $|z|=\sqrt{a^{2}+b^{2}}$ ---------- $z=-1-\displaystyle \frac{\sqrt{3}}{3}i$ Plot $(a,b)=(-1,-\displaystyle \frac{\sqrt{3}}{3})$ in the complex plane (see image, $-\displaystyle \frac{\sqrt{3}}{3}\approx -0.577)$ $|z|=\sqrt{(-1)^{2}+(-\frac{\sqrt{3}}{3})^{2}}=\sqrt{1+\frac{1}{3}}$ $=\displaystyle \sqrt{\frac{4}{3}}=\frac{2}{\sqrt{3}}=\frac{2\sqrt{3}}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.